بعض المعلومات عن جاهزي سامسونج Galaxy S7 و S7 Edge

كشفت شركة سامسونج اليوم عن أحدث الإضافات التابعة لسلسلة هواتف جالكسي، سامسونج جالكسي إس 7 Galaxy S7 وجالكسي إس 7 إيدج Galaxy S7 edge، وتأتي الهواتف بتصميم أنيق وأداء قوي إلى جانب ميزات الكاميرا المتقدمة وخاصية مقاومة الماء والذاكرة الخارجية.

وقال دي جي كوه، رئيس أعمال الاتصالات المتنقلة لدى شركة سامسونج للإلكترونيات: “نحن نؤمن بعالم أكثر إشراقاً وأكثر وضوحاً وأكثر ملاءمة وأكثر متعة، ونسعى جاهدين لتقديم رؤية جديدة عبر هاتفي Galaxy S7 و S7 Edge وذلك عبر التصميم الأنيق مع الوظائف والميزات المتعددة بالإضافة لتوفير تجربة محمول سلسة”. وأضاف: “نقدم للمستهلكين تقنيات تساعدهم في الحصول على المزيد من المنافع والمزايا، وسوف نستمر في دفع هذه الحدود إلى أبعد ما يمكن”.

كاميرا متقدمة: صور عالية الجودة بغض النظر عن الوقت أو الموقع

تقدم هواتف جالكسي الجديدة أول كاميرا مع بيكسل مزودج Dual Pixel في هاتف ذكي، بحيث تقدم صور أكثر إشراقاً وأكثر وضوحاً حتى في ظروف الإضاءة المنخفضة. ويتم ذلك بفضل التكنولوجيا الثورية لتقنية البيكسل المزدوج، والعدسة الأوضح ذات الفتحة الأوسع والبيكسل الأكبر، وتمتلك الكاميرا غالق أسرع وضبط تلقائي للصورة أكثر دقة حتى في ظروف الإضاءة المنخفضة. وتقدم الكاميرا الوضعية الجديدة Motion Panorama، والتي تجلب الحركة للصور البانورامية التقليدية، مما يتيح للمستخدم تجربة بصرية شاملة تماماً.

مفاهيم جديدة للتصميم والوظائف

يتكون تصميم هواتف الجديدة من الزجاج والمعدن، إلى جانب تصميم أنيق ومتين مع انحناءات هندسية توفر قبضة مريحة. وتتيح ميزة Always-On للمستخدمين تجربة مبسطة وسهلة الاستخدام بدون لمس الشاشة للحصول على التاريخ والوقت والتنبيهات دون عناء أو قلق حول فقدان مكالمة أو ملاحظات هامة. وتقدم هواتف جالاكسي إس 7 وإس 7 ايدج ميزة مقاومة الماء دون المساومة على تصميم الهواتف مع دعم معيار IP68 لمقاومة المياه والغبار.

ويوفر هاتف جالاكسي إس 7 ايدج تجربة متقدمة ومريحة مع زيادة كفاءة الاستخدام، وذلك من خلال إنشاء الاختصارات المهمة للمستخدم بسهولة أكبر، مثل البريد الإلكتروني، ووضع صورة شخصية، ووضع البانوراما، أو تطبيقات الطرف الثالث.

تعزيز الأداء: من الشحن إلى الألعاب

تقدم الهواتف الجديدة تقنية الشحن السلكية واللاسلكية السريعة، وتسمح علبة بطاقة الشريحة الهجينة للمستخدمين بإضافة بطاقة MicroSD يصل حجمها إلى 200 جيجابايت لتوفير مساحة تخزين إضافية، كما توفر هذه العلبة في بعض البلدان إمكانية استخدام بطاقتي سيم معاً.

كما قدمت سامسونج تحديثات مهمة لتحسين أداء الألعاب على الهواتف الجديدة، بحيث يسمح المعالج القوي والبطارية الأكبر بضمان وقت لعب أطول، ويحافظ نظام التبريد الداخلي للجهاز على الحفاظ عليه من ارتفاع درجة الحرارة.

وتشكل إضافة Game Launcher ميزة إضافية للاعبين بحيث تسمح لهم بإدارة استهلاك البطارية وتقليل التنبيهات، ويمكن للمستخدم تسجيل تجربة الألعاب الخاصة بهم أو مشاركة الشاشة الخاصة بالألعاب مع الآخرين، وتعطي واجهات التطبيقات البرمجية Vulkan API للمستخدمين القدرة على تشغيل الألعاب ذات الرسوميات العالية الأداء مع التقليل من استهلاك البطارية.

تجربة جالاكسي

تواصل سامسونج دفع حدود الأجهزة والبرمجيات والخدمات لتقديم أجهزة مصممة لتحسين كيفية ربط المستهلكين والمشاركة والتنظيم في سبيل الحصول على المزيد من الحياة، وتقوم الشركة بإعادة تعريف ما هو ممكن خارج حدود التكنولوجيا اليوم من خلال تقديم تجربة محمول سلسة.

وتسمح إمكانيات الربط السلس على وصل هواتف جالكسي إس 7 وجالكسي إس 7 ايدج بساعة Gear S2 Classic الجديدة لمراقبة أنشطة اللياقة البدنية، أو التوصيل مع نظارة الواقع الافتراضي Gear VR، بحيث تقوم سامسونج بإعادة تعريف ما هو ممكن ضمن تجربة المحمول وخارجها.

وبإمكان مستخدمي الهواتف الجديدة الحصول على خدمة دفع ممتازة بواسطة الهاتف المحمول عبر خدمة سامسونج باي Samsung Pay الآمنة والسهلة الاستخدام والتي تعمل في أي مكان تقريباً، والمحمية بواسطة KNOX وميزة قارئ بصمات الأصابع، والتي تعمل عبر تقنية الاتصال NFC وتقنية النقل المغناطيسي الآمن MST وتقنية الباركود، مما يجعل الدفع عبر الهاتف المتحرك في متناول مختلف الأشخاص.

وتتوفر الهواتف في الأسواق ابتداءً من منتصف شهر مارس القادم.

Galaxy S7 Galaxy S7 edge
نظام التشغيل أندرويد 6 مارشميلو أندرويد 6 مارشميلو
الشبكات LTE Cat.9 وWiFi 802.11 a/b/g/n/ac وMIMO وبلوتوث 4.2 وANT+ و USB 2.0و NFC LTE Cat.9 وWiFi 802.11 a/b/g/n/ac وMIMO وبلوتوث 4.2 وANT+ و USB 2.0و NFC
الأبعاد 142.4×69.6×7.9 ميليمتر 150.9×72.6×7.7 ميليمتر
الوزن 152 جرام 157 جرام
المعالج معالج ثماني النوى (٤ نوى بتردد ٢٫٣ جيجاهيرتز) + (٤ نوى بتردد ١٫٦ جيجاهيرتز)، ٦٤ بت، ١٤ نانومتر.

معالج رباعي النوى (٢ نواة بتردد ٢٫١٥ جيجاهيرتز) + (٢ نواة بتردد ١٫٦ جيجاهيرتز)، ٧٦ بت، ١٤ نانومتر.

معالج ثماني النوى (٤ نوى بتردد ٢٫٣ جيجاهيرتز) + (٤ نوى بتردد ١٫٦ جيجاهيرتز)، ٦٤ بت، ١٤ نانومتر.

معالج رباعي النوى (٢ نواة بتردد ٢٫١٥ جيجاهيرتز) + (٢ نواة بتردد ١٫٦ جيجاهيرتز)، ٧٦ بت، ١٤ نانومتر.

ذاكرة الوصول العشوائي 4 جيجابايت 4 جيجابايت
مساحة التخزين الداخلية 32 و64 جيجابايت مع وجود فتحة MicroSD 32 و64 جيجابايت مع وجود فتحة MicroSD
الشاشة 5.1 إنش بدقة 1440×2560 بيكسل وكثافة 577 بيكسل بالإنش من نوع Super AMOLED 5.5 إنش بدقة 1440×2560 بيكسل وكثافة 534 بيكسل بالإنش من نوع Super AMOLED
الكاميرا الخلفية كاميرا خلفية محسنة بدقة 12 ميجابيكسل مع فتحة عدسة f/1.7 مع ميزة مثبت الصورة البصري وخاصية التركيز التلقائي للصورة وفلاش LED مزدوج كاميرا خلفية محسنة بدقة 12 ميجابيكسل مع فتحة عدسة f/1.7 مع ميزة مثبت الصورة البصري وخاصية التركيز التلقائي للصورة وفلاش LED مزدوج
الكاميرا الأمامية بدقة 5 ميجابيكسل بدقة 5 ميجابيكسل
البطارية 3.000 ميلي أمبير تدعم خصائص الشحن السريع والشحن اللاسلكي والشحن اللاسلكي السريع 3.600 ميلي أمبير تدعم خصائص الشحن السريع والشحن اللاسلكي والشحن اللاسلكي السريع
Show or Hide HDD icon on desktop of mac

Show or Hide HDD icon on desktop of mac

Show or Hide HDD icon on desktop of mac

Finder

You can easily hide or show the “Macintosh HD” main hard drive from the desktop of OS X, along with any other internal volumes and removable drives by adjusting some Finder options.

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If you like to keep your disk drives available on the desktop for easy access like this, here’s what you can do to be sure they’re always visible on the Mac desktop:

How to Show (or Hide) Hard Drives, Disks, and Volumes on the Mac OS X Desktop

This feature is available in all versions of OS X:

  1. Go to the desktop of the Mac if you haven’t yet
  2. Launch the Finder Preferences from the “Finder” menu, or hit Command+,
  3. Under the ‘General’ tab, check or uncheck items you either want shown or hidden, respectively
  4. Close Finder preferences

The settings look like the following:

show or hide hard drive on mac desktop

These changes take effect immediately. Through these preferences you can adjust the visibility of Macintosh HD and other internal hard disks, external drives, CD’s, DVD’s, iPods, and even connected servers.

Macintosh HD is categorized under ‘Hard disks’ so if you leave it checked it will remain visible.

Each drive will have a unique icon visible on the desktop.

Hard drive icon

If you’re a minimalist or you just don’t like the desktop icons and the clutter they can cause, you can always hide all desktop icons in Mac OS X with a simple Terminal command as well.

Number Converting

Number Converting

Source: http://www.robotroom.com/

Number Systems

 

 

There are infinite ways to represent a number. The four commonly associated with modern computers and digital electronics are: decimal, binary, octal, and hexadecimal.

Decimal (base 10) is the way most human beings represent numbers. Decimal is sometimes abbreviated as dec.

Decimal counting goes:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, and so on.

Binary (base 2) is the natural way most digital circuits represent and manipulate numbers. (Common misspellings are “bianary”, “bienary”, or “binery”.) Binary numbers are sometimes represented by preceding the value with ‘0b’, as in 0b1011. Binary is sometimes abbreviated as bin.

Binary counting goes:
0, 1, 10, 11, 100, 101, 110, 111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111, 10000, 10001, and so on.

Octal (base 8) was previously a popular choice for representing digital circuit numbers in a form that is more compact than binary. Octal is sometimes abbreviated as oct.

Octal counting goes:
0, 1, 2, 3, 4, 5, 6, 7, 10, 11, 12, 13, 14, 15, 16, 17, 20, 21, and so on.

Hexadecimal (base 16) is currently the most popular choice for representing digital circuit numbers in a form that is more compact than binary. (Common misspellings are “hexdecimal”, “hexidecimal”, “hexedecimal”, or “hexodecimal”.) Hexadecimal numbers are sometimes represented by preceding the value with ‘0x’, as in 0x1B84. Hexadecimal is sometimes abbreviated as hex.

Hexadecimal counting goes:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F, 10, 11, and so on.

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All four number systems are equally capable of representing any number. Furthermore, a number can be perfectly converted between the various number systems without any loss of numeric value.

At first blush, it seems like using any number system other than human-centric decimal is complicated and unnecessary. However, since the job of electrical and software engineers is to work with digital circuits, engineers require number systems that can best transfer information between the human world and the digital circuit world.

It turns out that the way in which a number is represented can make it easier for the engineer to perceive the meaning of the number as it applies to a digital circuit. In other words, the appropriate number system can actually make things less complicated.

 

Fundamental Information Element of Digital Circuits

Almost all modern digital circuits are based on two-state switches. The switches are either on or off. It doesn’t matter if the switches are actually physical switches, vacuum tubes, relays, or transistors. And, it doesn’t matter if the ‘on’ state is represented by 1.8 V on a cutting-edge CPU core, -12 V on a RS-232 interface chip, or 5 V on a classic TTL logic chip.

Because the fundamental information element of digital circuits has two states, it is most naturally represented by a number system where each individual digit has two states: binary.

For example, switches that are ‘on’ are represented by ‘1’ and switches that are ‘off’ are represented by ‘0’. It is easy to instantly comprehend the values of 8 switches represented in binary as 10001101. It is also easy to build a circuit to display each switch state in binary, by having an LED (lit or unlit) for each binary digit.

 

Making Values More Compact

“Binary digit” is a little unwieldy to say over and over, so the term was contracted to “bit”. Not only is the term “binary digit” a little unwieldy, but so is the length of a binary number, since each digit can only represent one switch. As digital circuits grew more complex, a more compact form of representing circuit information became necessary.

An octal number (base 8) can be up to 1/3 the length of a binary number (base 2). 8 is a whole power of 2 (23=8). That means three binary digits convert neatly into one octal digit.

A hexadecimal number (base 16) can be up to 1/4 the length of a binary number. 16 is a whole power of 2 (24=16). That means four binary digits convert neatly into one hexadecimal digit.

Unfortunately, decimal (base 10) is not a whole power of 2. So, it is not possible to simply chunk groups of binary digits to convert the raw state of a digital circuit into the human-centric format.

Let’s see how to convert a number from binary.

 

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2. Binary Number Conversion

 

Binary to Octal

An easy way to convert from binary to octal is to group binary digits into sets of three, starting with the least significant (rightmost) digits.

Binary: 11100101 = 11 100 101
011 100 101 Pad the most significant digits with zeros if necessary to complete a group of three.

Then, look up each group in a table:

Binary: 000 001 010 011 100 101 110 111
Octal: 0 1 2 3 4 5 6 7

 

Binary = 011 100 101
Octal  = 3 4 5 = 345 oct

 

Binary to Hexadecimal

An equally easy way to convert from binary to hexadecimal is to group binary digits into sets of four, starting with the least significant (rightmost) digits.

Binary: 11100101 = 1110 0101

Then, look up each group in a table:

Binary: 0000 0001 0010 0011 0100 0101 0110 0111
Hexadecimal: 0 1 2 3 4 5 6 7

Binary: 1000 1001 1010 1011 1100 1101 1110 1111
Hexadecimal: 8 9 A B C D E F

 

Binary = 1110 0101
Hexadecimal = E 5 = E5 hex

 

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Binary to Decimal

They say there are only 10 people in this world: those that understand binary and those that don’t. Ha ha.

If you don’t get that joke, you’ll need a method to convert from binary to decimal. One method involves addition and multiplication.

  1. Start the decimal result at 0.
  2. Remove the most significant binary digit (leftmost) and add it to the result.
  3. If all binary digits have been removed, you’re done. Stop.
  4. Otherwise, multiply the result by 2.
  5. Go to step 2.

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Here is an example of converting 11100000000 binary to decimal:

Binary Digits   Operation   Decimal Result   Operation   Decimal Result
11100000000 +1 1 × 2 2
1100000000 +1 3 × 2 6
100000000 +1 7 × 2 14
00000000 +0 14 × 2 28
0000000 +0 28 × 2 56
000000 +0 56 × 2 112
00000 +0 112 × 2 224
0000 +0 224 × 2 448
000 +0 448 × 2 896
00 +0 896 × 2 1792
0 +0 1792 done.

Let’s try converting from decimal

 

3. Decimal Number Conversion

 

A repeated division and remainder algorithm can convert decimal to binary, octal, or hexadecimal.

  1. Divide the decimal number by the desired target radix (2, 8, or 16).
  2. Append the remainder as the next most significant digit.
  3. Repeat until the decimal number has reached zero.

Decimal to Binary

Here is an example of using repeated division to convert 1792 decimal to binary:

Decimal Number   Operation   Quotient   Remainder   Binary Result
1792 ÷ 2 = 896 0 0
896 ÷ 2 = 448 0 00
448 ÷ 2 = 224 0 000
224 ÷ 2 = 112 0 0000
112 ÷ 2 = 56 0 00000
56 ÷ 2 = 28 0 000000
28 ÷ 2 = 14 0 0000000
14 ÷ 2 = 7 0 00000000
7 ÷ 2 = 3 1 100000000
3 ÷ 2 = 1 1 1100000000
1 ÷ 2 = 0 1 11100000000
0 done.

 

Decimal to Octal

Here is an example of using repeated division to convert 1792 decimal to octal:

Decimal Number   Operation   Quotient   Remainder   Octal Result
1792 ÷ 8 = 224 0 0
224 ÷ 8 = 28 0 00
28 ÷ 8 = 3 4 400
3 ÷ 8 = 0 3 3400
0 done.

 

Decimal to Hexadecimal

Here is an example of using repeated division to convert 1792 decimal to hexadecimal:

Decimal Number   Operation   Quotient   Remainder   Hexadecimal Result
1792 ÷ 16 = 112 0 0
112 ÷ 16 = 7 0 00
7 ÷ 16 = 0 7 700
0 done.

The only addition to the algorithm when converting from decimal to hexadecimal is that a table must be used to obtain the hexadecimal digit if the remainder is greater than decimal 9.

Decimal: 0 1 2 3 4 5 6 7
Hexadecimal: 0 1 2 3 4 5 6 7

Decimal: 8 9 10 11 12 13 14 15
Hexadecimal: 8 9 A B C D E F

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The addition of letters can make for funny hexadecimal values. For example, 48879 decimal converted to hex is:

Decimal Number   Operation   Quotient   Remainder   Hexadecimal Result
48879 ÷ 16 = 3054 15 F
3054 ÷ 16 = 190 14 EF
190 ÷ 16 = 11 14 EEF
11 ÷ 16 = 0 11 BEEF
0 done.

Other fun hexadecimal numbers include: AD, BE, FAD, FADE, ADD, BED, BEE, BEAD, DEAF, FEE, ODD, BOD, DEAD, DEED, BABE, CAFE, C0FFEE, FED, FEED, FACE, BAD, F00D, and my initials DAC.

Now on to octal conversions…

 

4. Octal Number Conversion

 

Octal to Binary

Converting from octal to binary is as easy as converting from binary to octal. Simply look up each octal digit to obtain the equivalent group of three binary digits.

Octal: 0 1 2 3 4 5 6 7
Binary: 000 001 010 011 100 101 110 111

 

Octal  = 3 4 5
Binary = 011 100 101 = 011100101 binary

 

Octal to Hexadecimal

When converting from octal to hexadecimal, it is often easier to first convert the octal number into binary and then from binary into hexadecimal. For example, to convert 345 octal into hex:

(from the previous example)

Octal  = 3 4 5
Binary = 011 100 101 = 011100101 binary

Drop any leading zeros or pad with leading zeros to get groups of four binary digits (bits):
Binary 011100101 = 1110 0101

Then, look up the groups in a table to convert to hexadecimal digits.

Binary: 0000 0001 0010 0011 0100 0101 0110 0111
Hexadecimal: 0 1 2 3 4 5 6 7

Binary: 1000 1001 1010 1011 1100 1101 1110 1111
Hexadecimal: 8 9 A B C D E F

 

Binary = 1110 0101
Hexadecimal = E 5 = E5 hex

Therefore, through a two-step conversion process, octal 345 equals binary 011100101 equals hexadecimal E5.
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Octal to Decimal

Converting octal to decimal can be done with repeated division.

  1. Start the decimal result at 0.
  2. Remove the most significant octal digit (leftmost) and add it to the result.
  3. If all octal digits have been removed, you’re done. Stop.
  4. Otherwise, multiply the result by 8.
  5. Go to step 2.

Octal Digits   Operation   Decimal Result   Operation   Decimal Result
345 +3 3 × 8 24
45 +4 28 × 8 224
5 +5 229 done.

The conversion can also be performed in the conventional mathematical way, by showing each digit place as an increasing power of 8.

345 octal = (3 * 82) + (4 * 81) + (5 * 80) = (3 * 64) + (4 * 8) + (5 * 1) = 229 decimal

Converting from hexadecimal is next…

 

5. Hexadecimal Number Conversion

Hexadecimal to Binary

Converting from hexadecimal to binary is as easy as converting from binary to hexadecimal. Simply look up each hexadecimal digit to obtain the equivalent group of four binary digits.

Hexadecimal: 0 1 2 3 4 5 6 7
Binary: 0000 0001 0010 0011 0100 0101 0110 0111

Hexadecimal: 8 9 A B C D E F
Binary: 1000 1001 1010 1011 1100 1101 1110 1111

 

Hexadecimal = A 2 D E
Binary = 1010 0010 1101 1110 = 1010001011011110 binary

 

Hexadecimal to Octal

When converting from hexadecimal to octal, it is often easier to first convert the hexadecimal number into binary and then from binary into octal. For example, to convert A2DE hex into octal:

(from the previous example)

Hexadecimal = A 2 D E
Binary = 1010 0010 1101 1110 = 1010001011011110 binary

Add leading zeros or remove leading zeros to group into sets of three binary digits.

Binary: 1010001011011110 = 001 010 001 011 011 110

Then, look up each group in a table:

Binary: 000 001 010 011 100 101 110 111
Octal: 0 1 2 3 4 5 6 7

 

Binary = 001 010 001 011 011 110
Octal = 1 2 1 3 3 6 = 121336 octal

Therefore, through a two-step conversion process, hexadecimal A2DE equals binary 1010001011011110 equals octal 121336.

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Hexadecimal to Decimal

Converting hexadecimal to decimal can be performed in the conventional mathematical way, by showing each digit place as an increasing power of 16. Of course, hexadecimal letter values need to be converted to decimal values before performing the math.

Hexadecimal: 0 1 2 3 4 5 6 7
Decimal: 0 1 2 3 4 5 6 7
Hexadecimal: 8 9 A B C D E F
Decimal: 8 9 10 11 12 13 14 15

A2DE hexadecimal:
= ((A) * 163) + (2 * 162) + ((D) * 161) + ((E) * 160)
= (10 * 163) + (2 * 162) + (13 * 161) + (14 * 160)
= (10 * 4096) + (2 * 256) + (13 * 16) + (14 * 1)
= 40960 + 512 + 208 + 14
= 41694 decimal

Finally, why you might choose one number system over another…

 

6. Selecting a Numbering System

 

The appropriate numbering system to represent a value depends on the application. There are advantages and disadvantages to each numbering system.

When interfacing with non-engineers, decimal remains the numbering system of choice. For example, I’d have heart attack if the IRS told me that I owed them 1000000 dollars, when they actually meant to say 64 decimal.

Modern computers have lots of memory and disk space for programs. However, many low-end microcontrollers can be quite tight on space. Outputting a decimal value to a serial port or display requires the number be divided by 10 to break off each digit. Depending on the capabilities of the microcontroller, the divide-by-ten routine alone can take up more room than an entire hexadecimal output routine!

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When diagnosing an output pin logic problem, it isn’t immediately helpful to see that the microcontroller’s port B is set to 180 decimal. I’d prefer to see the pins as 10110100 binary. The same thing is true when looking at bit flags in memory. A disadvantage of binary is that it gets lengthy fairly quickly.

When debugging dumps of memory, disks, or data streams on modern microcontroller and computers, hexadecimal provides a compact format that is easy to break into bytes and convert into bits. In my software career, I routine examine lengthy log files detailing all the bytes sent over the air on the wireless networks.

Octal has fallen out of usage over the last thirty years due to microprocessors and microcontrollers processing data in bit chunks that are not evenly divisible by 3 (4-bit, 8-bit, 16-bit, 32-bit, 64-bit) . Octal does have the advantage of requiring only number symbols (0-8), as opposed to hexadecimal (0-9, A-F). So, octal still finds some limited usage on numeric-only displays.

To summarize, I switch between using binary, decimal, and hexadecimal on a regular basis, depending which format most clearly expresses the data that the number represents.

Multiarea OSPF 4

CCNP ROUTE Practice Exam:

Multiarea OSPF 4

Chris Bryant, “The Computer Certification Bulldog”

Here’s the 4th practice exam in this series. Dig in!

Question 1:

You’re configuring an OSPF ASBR, and have determined that all the routes injected into OSPF via redistribution can be summarized with the address 23.0.0.0 /12.

What is the full OSPF command to advertise this summary into the OSPF domain in place of the specific routes?

Question 2:

You’re performing two-way route redistribution between an EIGRP AS and an OSPF domain. On the OSPF routers, what is the default routing table code for the routes learned from EIGRP?

Extra credit: What code will appear on the EIGRP routers next to any routes that are injected into the EIGRP AS from OSPF?

Consider the following OSPF configuration and answer the following questions.

R4(config)#router ospf 1

R4(config-router)#network 172.12.0.0 0.0.0.255 area 0

R4(config-router)#network 1.1.1.1 0.0.0.0 area 1

R4(config-router)#router-id 20.1.1.1

< router reloaded at this point >

R4(config)#interface loopback0

R4(config-if)#ip address 50.1.1.1 255.255.255.255

Question 3:

Is that a legal configuration? If not, why not?

Question 4:

What is the OSPF process number?

Question 5:

What is the RID of this particular router?

Question 6:

Is this router an ABR, ASBR, both, or neither?

Explain why this router is or isn’t an ABR.

Explain why this router is or isn’t an ASBR.

This ends the questions about that router configuration.

Question 7:

An OSPF total stub router can contain what route types?

A. Default route only

B. E2 routes and a default route

C. E1 routes and a default route

D. Intra-area routes and a default route

E. Inter-area routes and a default route

Answers:

1. The full command is:

summary-address 23.0.0.0 255.240.0.0

2. These routes will appear as OSPF External Type 2 routes and will have a router table code of “O E2”.

The routes that are redistributed from OSPF into EIGRP will appear in the EIGRP routing tables with a code of “D EX”.

3. Yep, it’s legal.

4. The OSPF process number is 1, as indicated by the router ospf 1 command.

5. The OSPF RID was hardcoded as 20.1.1.1, and it took effect after the router reload I mentioned.

6. This router is an ABR since it borders Area 1 and Area 0.

There is no route redistribution shown on this router, so it’s not an ASBR.

7. “D”. The routing table of a total stub router can contain intra-area routes and a default inter-area route using the ABR as the next hop.

Thanks for taking this CCNP practice exam – here are the other OSPF multiarea exams!

OSPF Questions 2

OSPF Questions 2

Question 1

Into which two types of areas would an area border router (ABR) inject a default route? (Choose two)

A. the autonomous system of a different interior gateway protocol (IGP)
B. area 0
C. totally stubby
D. NSSA
E. stub
F. the autonomous system of an exterior gateway protocol (EGP)

 

Answer: C E

Explanation

Both stub area & totally stubby area allow an ABR to inject a default route. The main difference between these 2 types of areas is:

+ Stub area replaces LSA Type 5 (External LSA – created by an ASBR to advertise network from another autonomous system) with a default route
+ Totally stubby area replaces both LSA Type 5 and LSA Type 3 (Summary LSA – created by an ABR to advertise network from other areas, but still within the AS, sometimes called interarea routes) with a default route.

Below summarizes the LSA Types allowed and not allowed in area types:

Area Type Type 1 & 2 (within area) Type 3 (from other areas) Type 4 Type 5 Type 7
Standard & backbone Yes Yes Yes Yes No
Stub Yes Yes No No No
Totally stubby Yes No No No No
NSSA Yes Yes No No Yes
Totally stubby NSSA Yes No No No Yes

Question 2

Which three restrictions apply to OSPF stub areas? (Choose three)

A. No virtual links are allowed.
B. The area cannot be a backbone area.
C. Redistribution is not allowed unless the packet is changed to a type 7 packet.
D. The area has no more than 10 routers.
E. No autonomous system border routers are allowed.
F. Interarea routes are suppressed.

 

Answer: A B E

Question 3

Refer to the partial configurations in the exhibit. What address is utilized for DR and BDR identification on Router1?

Router1#show run**** output omitted ******

interface serial1/1
ipv6 address 2001:410:FFFE:1::64/64
ipv6 ospf 100 area 0
!
interface serial2/0
ipv6 address 3FFF:B00:FFFF:1::2/64
ipv6 ospf 100 area 0
!
ipv6 router ospf
router-id 10.1.1.3

A. the serial 1/1 address
B. the serial 2/0 address
C. a randomly generated internal address
D. the configured router-id address

 

Answer: D

Explanation

In OSPFv3 and OSPF version 2, the router uses the 32-bit IPv4 address to select the router ID for an OSPF process. The router ID selection process for OSPFv3 is described below (same as OSPF version 2):

1. The router ID is used if explicitly configured with the router-id command.
2. Otherwise, the highest IPv4 loopback address is used.
3. Otherwise, the highest active IPv4 address.
4. Otherwise, the router ID must be explicitly configured.

In this case the router ID 10.1.1.3 is explicitly configured -> D is correct.

Question 4

By default, which statement is correct regarding the redistribution of routes from other routing protocols into OSPF?

A. They will appear in the OSPF routing table as type E1 routes.
B. They will appear in the OSPF routing table as type E2 routes.
C. Summarized routes are not accepted.
D. All imported routes will be automatically summarized when possible.
E. Only routes with lower administrative distances will be imported.

 

Answer: B

Explanation

Type E1 external routes calculate the cost by adding the external cost to the internal cost of each link that the packet crosses while the external cost of E2 packet routes is always the external cost only. E2 is useful if you do not want internal routing to determine the path. E1 is useful when internal routing should be included in path selection. E2 is the default external metric when redistributing routes from other routing protocols into OSPF -> B is correct.

Question 5

Which statement is true about OSPF Network LSAs?

A. They are originated by every router in the OSPF network. They include all routers on the link, interfaces, the cost of the link, and any known neighbor on the link.
B. They are originated by the DR on every multi-access network. They include all attached routers including the DR itself.
C. They are originated by Area Border Routers and are sent into a single area to advertise destinations outside that area.
D. They are originated by Area Border Router and are sent into a single area to advertise an Autonomous System Border Router.

 

Answer: B

Explanation

Popular LSA Types are listed below:

LSA Type Description Details
1 Router LSA Generated by all routers in an area to describe their directly attached links
2 Network LSA Advertised by the DR of the broadcast network (does not cross ABR)
3 Summary LSA Advertised by the ABR of originating area
4 Summary LSA Generated by the ABR of the originating area to advertise an ASBR to all other areas in the autonomous system
5 AS external LSA Used by the ASBR to advertise networks from other autonomous systems
7 Defined for NSSAs Generated by an ASBR inside a Not-so-stubby area (NSSA) to describe routes redistributed into the NSSA

Question 6

Refer to the exhibit. OSPF is configured on all routers in the network. On the basis of the show ip ospf neighbor output, what prevents R1 from establishing a full adjacency with R2?

show_ip_ospf_neighbor.jpg

A. Router R1 will only establish full adjacency with the DR and BDR on broadcast multiaccess networks.
B. Router R2 has been elected as a DR for the broadcast multiaccess network in OSPF area
C. Routers R1 and R2 are configured as stub routers for OSPF area 1 and OSPF area 2.
D. Router R1 and R2 are configured for a virtual link between OSPF area 1 and OSPF area 2.
E. The Hello parameters on routers R1 and R2 do not match.

 

Answer: A

Explanation

From the output, we learn that R4 is the DR and R3 is the BDR so other routers will only establish full adjacency with these routers. All other routers have the two-way adjacency established -> A is correct.

Question 7

Refer to the exhibit. On the basis of the configuration provided, how are the Hello packets sent by R2 handled by R5 in OSPF area 5?

OSPF_Hello_packets.jpg

A. The Hello packets will be exchanged and adjacency will be established between routers R2 and R5.
B. The Hello packets will be exchanged but the routers R2 and R5 will become neighbors only.
C. The Hello packets will be dropped and no adjacency will be established between routers R2 and R5.
D. The Hello packets will be dropped but the routers R2 and R5 will become neighbors.

 

Answer: C

Explanation

Recall that in OSPF, two routers will become neighbors when they agree on the following: Area-id, Authentication, Hello and Dead Intervals, Stub area flag.

We must specify Area 5 as a stub area on the ABR (R2) and all the routers in that area (R5 in this case). But from the output, we learn that only R2 has been configured as a stub for Area 5. This will drop down the neighbor relationship between R2 and R5 because the stub flag is not matched in the Hello packets of these routers.

Question 8

When an OSPF design is planned, which implementation can help a router not have memory resource issues?

A. Have a backbone area (area 0) with 40 routers and use default routes to reach external destinations.
B. Have a backbone area (area 0) with 4 routers and 30,000 external routes injected into OSPF.
C. Have less OSPF areas to reduce the need for interarea route summarizations.
D. Have multiple OSPF processes on each OSPF router. Example, router ospf 1, router ospf 2

 

Answer: A

Question 9

When verifying the OSPF link state database, which type of LSAs should you expect to see within the different OSPF area types? (Choose three)

A. All OSPF routers in stubby areas can have type 3 LSAs in their database.
B. All OSPF routers in stubby areas can have type 7 LSAs in their database.
C. All OSPF routers in totally stubby areas can have type 3 LSAs in their database.
D. All OSPF routers in totally stubby areas can have type 7 LSAs in their database.
E. All OSPF routers in NSSA areas can have type 3 LSAs in their database.
F. All OSPF routers in NSSA areas can have type 7 LSAs in their database.

 

Answer: A E F

Explanation

Below summarizes the LSA Types allowed and not allowed in area types:

Area Type Type 1 & 2 (within area) Type 3 (from other areas) Type 4 Type 5 Type 7
Standard & backbone Yes Yes Yes Yes No
Stub Yes Yes No No No
Totally stubby Yes No No No No
NSSA Yes Yes No No Yes
Totally stubby NSSA Yes No No No Yes

Popular LSA Types are listed below:

LSA Type Description Details
1 Router LSA Generated by all routers in an area to describe their directly attached links
2 Network LSA Advertised by the DR of the broadcast network (does not cross ABR)
3 Summary LSA Advertised by the ABR of originating area
4 Summary LSA Generated by the ABR of the originating area to advertise an ASBR to all other areas in the autonomous system
5 AS external LSA Used by the ASBR to advertise networks from other autonomous systems
7 Defined for NSSAs Generated by an ASBR inside a Not-so-stubby area (NSSA) to describe routes redistributed into the NSSA

Question 10

You are troubleshooting an OSPF problem where external routes are not showing up in the OSPF database. Which two options are valid checks that should be performed first to verify proper OSPF operation? (Choose two)

A. Are the ASBRs trying to redistribute the external routes into a totally stubby area?
B. Are the ABRs configured with stubby areas?
C. Is the subnets keyword being used with the redistribution command?
D. Is backbone area (area 0) contiguous?
E. Is the CPU utilization of the routers high?

 

Answer: A C

Explanation

A totally stubby stubby area cannot have an ASBR so it will discard this type of LSA (LSA Type 5) -> A is a valid check.

Each stubby area needs an ABR to communicate with other areas so it is normal -> B is not a valid check.

When pulling routes into OSPF, we need to use the keyword “subnets” so that subnets will be redistributed too. For example, if we redistribute these EIGRP routes into OSPF:

+ 10.0.0.0/8
+ 10.10.0.0/16
+ 10.10.1.0/24

without the keyword “subnets”

router ospf 1
redistribute eigrp 1

Then only 10.0.0.0/8 network will be redistributed because other routes are not classful routes, they are subnets. To redistribute subnets we must use the keyword “subnets”

router ospf 1
redistribute eigrp 1 subnets

-> C is a valid check.

We don’t need to care if area 0 is contiguous or not -> D is not a valid check.

CPU utilization cannot be the cause for this problem -> E is not a valid check.

For this question, please read our tutorial about OSPF LSA Types for more detail.